Question

The acid dissociation constant for boric acid, h3bo3, is 5.8 x 10-10. calculate the dissociation constant, kb , of the hydrogen borate ion ( hbo32- ).

Answer 1

The answer is 5.8x10^-10. I did the math and checked other sources as well.

Answer 2

Answer: The base dissociation constant for a conjugate base is
`1.72* 10^(-5)`

Step-by-step explanation:

To calculate the base dissociation constant for the given acid dissociation constant, we use the equation:

`K_w=K_b* K_a`

where,

`K_w` = Ionic product of water =
`10^(-14)`

`K_a` = Acid dissociation constant =
`5.8* 10^(-10)`

`K_b` Base dissociation constant = ?

Putting values in above equation, we get:

`10^(-14)=5.8* 10^(-10)* K_b\\\\K_b=0.172* 10^(-4)=1.72* 10^(-5)`

Hence, the base dissociation constant for a conjugate base is
`1.72* 10^(-5)`