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A hill that has a 12.0% grade is one that rises 12.0 m vertically for every 100.0 m of distance in the horizontal direction. at what angle is such a hill inclined above the horizontal?

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We are given the vertical component (y) and the horizontal component (x) of the slope. In this scenario, we use the tan function to solve for the angle θ:

tan θ = y / x

tan θ = 12 / 100

θ = tan^-1 (0.12)

θ = 6.84°

User Kim Tang
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