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The density (in g/cm3) of a gold nugget that has a volume of 1.68 cm3 and a mass of 32.4 g is __________.

User Amar
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2 Answers

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Answer:

Density of the gold nugget,
\rho=19.28\ g/cm^3

Step-by-step explanation:

It is given that,

Mass of the gold nugget, m = 32.4 g

Volume of the gold nugget
V=1.68\ cm^3

We need to find the density of the gold nugget. The total mass divided by total volume of an substance is called its density. Its formula is given by :


\rho=(m)/(V)


\rho=(32.4\ g)/(1.68\ cm^3)


\rho=19.28\ g/cm^3

So, the density of the metal ball is
19.28\ g/cm^3. Hence, this is the required solution.

User Shogunivar
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The density of a substance is extensive even though its unit components, mass and volume, are intensive properties. At a certain temperature and pressure, the density of a substance is constant. It is the ratio of the substance's mass to volume.

Density = Mass/Volume
Density = 32.4 g/1.68 cm³
Density = 19.29 g/cm³
User Usman Mahmood
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