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A chemist mixes an 8% hydrochloric acid solution with a 5% hydrochloric acid solution. How many millilitersof the 5% solution should the chemist use to make a 750-milliliter solution that is 7% hydrochloric acid?

User Renklus
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let x be volume of 5% acid and y be volume of the 8%


x + y = 750 and
0.05x + 0.08y = 0.07*750 = 52.5

from first equation y = 750 - x so substituting in the second equation:-

0.05x + 0.08(750 - x) = 52.5
0.05 - 0.08x = 52.5 - 60
-0.03x = -7.5
x = -7.5 / -0.3 = 250 mls <------ answer

User Arijit Panda
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