We want to find P-value of (86<X<92)
Start by working out the z- score for X=86 and X=92
for X = 86
z-score = [86-80]/6 = 1
for X = 92
z-score = [92-80]/6 = 2
P(1<Z<2) = P(Z<2) - P(Z<1)
Read P(Z<2) and P(Z<1) on the z-table
P(1<Z<2) = 0.9772 - 0.8413 = 0.1359
Probability of a student achieve a mark between 86 and 92 is 0.1359 and out of 100, this is 0.1359 Ă— 100 = 13.59
The closest number of student is = 9 students