Question

Need a quick answer!!!

A container of what volume would be required to store 60.0 moles of a gas at a pressure of 20.0 atm and a temperature of 50.0 Celsius?

79.6 L
12.3 L
1250 L
8060 L

Answer 1

n: 60 mol
p: 20 atm = 20×1013hPa = 20260 hPa
T: 50°C = 323 K
R: 83,14 hPa·dm³/mol·K
V: ?
.................

pV = nRT
V = nRT/p
V = (60×83,14×323)/20260
V = 79,529 dm³ ≈ 79,6 dm³

79,6 dm³ = 79,6 L

:•)