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2 votes
There are 15 cherry, 17 grape, and 14 orange juice boxes in the cooler. What is the probability of randomly selecting a cherry then selecting a grape without replacement?

Question 3 options:

17/138


119/1058


136/1035


29/46

User Levan
by
8.0k points

2 Answers

4 votes
15 cherry, 17 grape, and 14 orange....total of 46 juice boxes

P(cherry) = 15/46
without replacing
P(grape) = 17/45 (I put it over 45 because since the 1st was not replaced, we have 1 less juice box)

P (both events happening) = 15/46 * 17/45 = 17/138 <==

User JJAN
by
6.9k points
0 votes
15 +17 +14 = 46 juice boxes total

15 cherry = 15/46

17 grape = 17/45

15/46 * 17/45 = 17/138
User Joachim Seminck
by
8.5k points