Question

Find the equation for the circle with center (3,-4) and passing through (-3,-2)

Answer 1

The equation form is as follows:
`(x-x_0)^2+(y-y_0)^2=r^2` where
`(x_0,y_0)` is the center and
`r` is the radius.
So
`r= √((3+3)^2+(-4+2)^2)= √(85)`
hence the equation is

`(x-3)^2+(y+4)^2=85`

`x^2+y^2-6x+8y-60=0.`