Question

What is the equation of a line passing through the point (a, b) and having a slope of b?

y = −bx − b(1 − a)
y = bx − b(a − 1)
y=1/bx+b(a-1)
y=-1/bx+b(1-a)

Answer 1

y - y1 = m(x - x1)....slope = b, points (a,b)

y - b = b(x - a)
y - b = bx - ba
y = bx - ba + b
y = bx - b(a - 1) <===

Answer 2

The answer is y=bx-b(a-1), because when x=a then y=b.