Question

What is the concentration of naoh needed to get a solution with ph 12.25?

Answer 1

pOH = 14-pH = 14-12,25 = 1,75

pOH = -log[OH-]
[OH-] = 10^-pOH
[OH-] = 10^-1,75
[OH-] = 0,01778 mol/dm³

[NaOH] = [OH-] = 0,01778M

:•)

Answer 2

Answer: 0.018 M

Step-by-step explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.

`pH=-\log [H^+]`

Given: pH= 12.25

`pH+pOH=14`

`pOH=14-12.25=1.75`

`pOH=-log[OH^-]`

`1.75=-log[OH^-]`

`[OH^-]=0.018M`

`NaOH\rightarrow Na^++OH^-`

Thus as 1 mole of
`NaOH` gives 1 mole of
`OH^-` thus concentration of
`NaOH` will be 0.018M.