19.6k views
1 vote
When you solve the equation x^3-3x^2+2x=0, how many roots are greater than 1/2?

1 Answer

5 votes
hello :
x^3-3x^2+2x=0
x(x²-3x+2) = 0
x(x-1)(x-2) = 0
x = 0 or x-1 = 0 or x-2= 0
x = 0 or x = 1 or x = 2
two roots are greater than 1/2 : 1 and 2
User Gifty
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories