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If SecO = 13/12 and O is between 3pi/2 and 2pi, find the exact values in reduced form for:A.)Tan OB.)Sin(20) C.)Cos(O/2)

User Fejta
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1 Answer

12 votes
12 votes

Identify and Set Up

We are given a question on trigonometric identities.

Our approach is to:

First, we resolve the identity, sec,

- Get the sides and angles of our triangles

- Resolve the other identities.

Execute


\sec O=(1)/(\cos O)=(h)/(a)=(13)/(12)

We now have for ourselves a right angled triangle with hypothenuse 13 and adjacent 12.

From this, we know that the opposite side is:


x=\sqrt[]{13^2-12^2}=\sqrt[]{25}=5

A)

Tan O


\tan 0=\frac{\text{opp}}{\text{hyp}}=(5)/(12)

B)

Sin2O


\sin 2O=2\sin O\cos O

Hence, we have to find sin O and cos O


\begin{gathered} \sin O=\frac{\text{opp}}{\text{hyp}}=(5)/(13) \\ \cos O=\frac{\text{adj}}{\text{hyp}}=(12)/(13) \end{gathered}

Hence, we have:


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If SecO = 13/12 and O is between 3pi/2 and 2pi, find the exact values in reduced form-example-1
User Cox
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2.9k points