Question

Find the average rate of change of f(x)=9x^2−8 on the interval [1,b] . Your answer will be an expression involving b

Answer 1

Given:

Function is

`f(x)=9x^2-8`

On interval [1, b]

Required:

Find the average rate of change?

Step-by-step explanation:

The average rate change of f(x) on the interval. [a, b] is

`(f(b)-f(a))/(b-a)`

We have that a = 1, b = b,

`f(x)=9x^2-8`

Thus

`\begin{gathered} (f(b)-f(a))/(b-a)=(-8+9b^2-(-8+91^2))/(b-(-1)) \\ =(9b^2-9)/(b-1) \\ =9b+9 \end{gathered}`

Answer:

Hence, this is the answer.