232k views
24 votes
How many moles of Al2O3 will be produced if 1.35 moles of Fe are produced?

User Tura
by
4.6k points

1 Answer

2 votes

Answer:

0.675 mol

Step-by-step explanation:

Step 1: Write the balanced equation

2 Al + Fe₂O₃ ⇒ 2 Fe + Al₂O₃

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of Fe to Al₂O₃ is 2:1.

Step 3: Calculate the moles of Al₂O₃ produced when 1.35 moles of Fe are produced

We will use the established molar ratio.

1.35 mol Fe × 1 mol Al₂O₃/2 mol Fe = 0.675 mol Al₂O₃

User Chan Austin
by
4.3k points