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Find the maximum and minimum values of f(x)=x^3-3x^2-9x + 2

User Noobzie
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1 Answer

3 votes

Answer:

minimum point is (3, -25) and maximum point is (-1, 7)

Explanation:

f(x) = x³ - 3x² - 9x + 2

Differentiate:

f'(x) = 3x² - 6x - 9

Equal f'(x) to zero and solve to find values of x:

f'(x) = 0

3x² - 6x - 9 = 0

(x - 3)(x + 1) = 0

x = 3, -1

Plug in values of x into original function to find coordinates of turning/stationary points: (3, -25) and (-1, 7)

Differentiate again:

f''(x) = 6x - 6

Plug in x value of stationary points to find nature of point:

f''(3) = 6(3) - 6 = 12 > 0 ⇒ minimum

f''(-1) = 6(3) - 6 = -12 < 0 ⇒ maximum

Therefore, the minimum point is (3, -25) and maximum point is (-1, 7)

User Papaya Labs
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