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A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = −16t2 + 36t + 5. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?

A. 2.25 s; 5 ft


B. 1.13 s; 25.25 ft


C. 1.13 s; 27.5 ft


D. 1.13 s; 65.75 ft

2 Answers

1 vote

Answer:D. 1.13 s; 65.75 ft

User Gee Bee
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A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = −16t2 + 36t + 5. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?


A. 2.25 s; 5 ft


B. 1.13 s; 25.25 ft


C. 1.13 s; 27.5 ft


D. 1.13 s; 65.75 ft <====

User Hypnoz
by
8.9k points
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