Question

what volume of nitrous oxide (N20) can be produced from the decomposition of 0.55 moles of ammonium nitrate (NH4NO3). NH4NO3 (s) àN2O (g) + 2H2O (g)

Answer 1

NH4NO3 ==> N2O + 2H2O

Answer 2

1 mol of gas at STP ⇒22,4dm³
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1 mol....................22,4dm³
NH₄NO₃(s) ----> N₂O(g) + 2H₂O(g)
0,55 mol................. X

X = (0,55×22,4)/1
X = 12,32 dm³ N₂O

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