The formula required is expressed as
Po = [d(1 - (1 + r/k)^- nk]/(r/k)
Where
Po is the balance in the account initially
d is the regular amount being withdrawn
r is the interest rate
k is the number of compounding periods in one year
n is the number of years
From the information given,
d = 2100
r = 2/100 = 0.02
n = 19
k = 52(assuming there are 52 weeks in a year)
Thus,
Po = [2100(1 - (1 + 0.02/52)^- 19 * 52]/(0.02/52)
Po = [2100(1 - (1.00038461538)^- 988]/0.00038461538
Po = 2100(0.3161)/0.00038461538
Po = 1725906
The amount that the account needs is $1725906