Question

The distance between point (-4,6) and (3,-7)

Answer 1

By the distance formula,

`d = \sqrt{( x_2 - x_1) {}^(2) + (y_2 - y_1 {)}^(2) }`

Here,

`x_1 = -4`

`y_1 = 6`

`x_2 = -7`

`y_2 = 3`

Hence,

`d = \sqrt{( {(-7 )+(- 4))}^(2) + {( 3 + 6)}^(2) }`

`d = \sqrt{ {(-11)}^(2) + {9}^(2) }`

`d = √(121+ 81)`

`d = √(202)`

Answer 2

disatnce bewteen (x1,y1) and (x2,y2) is

`D=√((x_1-x_2)^2+(y_1-y_2)^2)`


so disatnce between (-4,6) and (3,-7) is

`D=√((-4-3)^2+(6-(-7))^2)`

`D=√((-7)^2+(6+7)^2)`

`D=√(49+(13)^2)`

`D=√(49+169)`

`D=√(218)`

the disatnce is √218 units or aprox 14.7648 units