Question

If you know that nine to the third power = 729, describe how to find nine to the fourth power without having to multiply four 9s.

Answer 1

remember

`(x^m)(x^n)=x^(m+n)`

so

`(9^3)(9^1)=9^(3+1)=9^4`
9^3=729
so


`(729)(9)=9^4`
that's how yo do it, muliply 9 by 729