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Solve for x n(17+x)=34x−r

2 Answers

5 votes

Answer:


(17n+r)/(34-n)=x

Explanation:

Given :
n(17+x)=34x−r

To Find : Find the value of x

Solution :


n(17+x)=34x−r


17n+xn=34x−r


17n+r=34x−xn


17n+r=x(34−n)


(17n+r)/(34-n)=x

Hence the value of x is
(17n+r)/(34-n)

User Tom Pohl
by
6.2k points
4 votes

Answer:


x=(r+17n)/(34-n).

Explanation:

We have been given an equation
n(17+x)=34x-r. We are asked to solve for x.

Using distributive property, we will get:


17n+xn=34x-r

Now, we will subtract 34x from both sides of our equation.


17n+xn-34x=34x-34x-r


17n+xn-34x=-r

Let us subtract 17n from both sides of our equation.


17n-17n+xn-34x=-r-17n


xn-34x=-r-17n

Now we will factor out x from left side of our equation.


x(n-34)=-r-17n

Upon dividing both sides of our equation by
(n-34), we will get:


(x(n-34))/((n-34))=(-r-17n)/((n-34))


x=(-r-17n)/((n-34))

Now we will factor out negative sign as shown:


x=(-(r+17n))/(-(-n+34))


x=(r+17n)/(34-n)

Therefore, the value of x is
x=(r+17n)/(34-n).

User Comrade
by
6.5k points
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