30.1k views
4 votes
At what value of x does the graph of the following function F(x) have a vertical asymptote? F(x)=1/x-1

2 Answers

0 votes

X = 1

This is A_(P)Ex verified

User Falcon
by
8.0k points
5 votes
Vertical asymptotes are the x-values for which a particular function is undefined;
With linear reciprocal functions like the one given, it will be when the denominator equates to 0 as it is impossible to divide any number by 0;
So we just have to equate the denominator to 0 and rearrange to give x:
x - 1 = 0
x = 1
The line x = 1 is the vertical asymptote for this function.

Horizontal asymptotes are the y-values for which a particular function is undefined;
Finding the horizontal asymptote for linear reciprocal functions is quite simple;
For this kind of function, where there is no x term in the numerator, the horizontal asymptote is just equivalent to the constant added to the fraction (note: having no added constant is the same as having an added 0);
So:
F(x) = 1/(x - 1) = (1/(x - 1)) + 0
The horizontal asymptote is y = 0 for this function.

If it was F(x) = (1/(x - 1)) + 1, the horizontal asymptote would be y = 1.
User Patrick Maupin
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories