Question

6+2i

------
3+3i

please help me! i do NOT want the equation to look like, 6 + ((2 * i) / 3) - (3 * i)

Answer 1

`(6+2i)/(3+3i)=(6+2i)/(3+3i)*(3-3i)/(3-3i)`

`(6+2i)/(3+3i)=(18-18i+6i-6i^(2))/(9-9i+9i-9i^(2))`

`(6+2i)/(3+3i)=(18-12i+6)/(9+9)`

`(6+2i)/(3+3i)=(24-12i)/(18)`

`(6+2i)/(3+3i)=(12(2-i))/(18)`

`(6+2i)/(3+3i)=(2(2-i))/(3)`

`(6+2i)/(3+3i)=(2)/(3)(2-i)`

`(6+2i)/(3+3i)=(4)/(3)-(2i)/(3)`