1 Answer

Tonino · Answer 1 · 2018-04-02T05:24:29+0000

The probability of r successes in n trials is

C(n,r)p^r(1-p)^(n-r)

where C(n,r) is the number of combinations of n things taken r at a time...

C(n,r)=(n!)/(r!(n-r)!)

Define "success" as getting a 6 on the die. Then the probability of success is
p=(1)/(6)

and the probability of "failure" is
1-p=(5)/(6)

.

The probility is
$C(4,2)\left((1)/(6)\right)^2 \left((5)/(6)\right)^2=6\left((1)/(36)\right) \left( (25)/(36)\right)=0.11574=11.6%$

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