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Find the sum of the following infinite geometric series, if it exists. 1/3+1/9+1/27+1/81+...

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The given infinite geometric series is

(1)/(3),\, (1)/(9), \, (1)/(27) , \, (1)/(81) , \, ...,

The first term is a = 1/3.
The common ratio is r = 1/3.

The sum is

(a)/(1-r)= (1/3)/(1 - 1/3) = (1)/(2)

Answer: 1/2
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