Question

Whist are the solution of log(t-3)=log(17-4t)

Answer 1

yay
remember that you can do anything to an equation as long as you do it to both sides

also
log(a)-log(b)=log(a/b)
and
if no base is stated, then probably base 10
also,
`log_a(b)=c` translates to
`a^c=b`


so

log(t-3)=log(17-4t)
minus log(17-4t) from both sides
log(t-3)-log(17-4t)=0

`log((t-3)/(17-4t))=0`
translate
remember, base 10

`10^0=(t-3)/(17-4t)`

`1=(t-3)/(17-4t)`
times both sides by 17-4t
17-4t=t-3
add 4t both sides
17=5t-3
add 3 both sides
20=5t
divide both sides by 5
4=t
t=4