Question

Suppose that a particular artillery piece has a range r = 9010 yards . find its range in miles. use the facts that 1mile=5280ft and 3ft=1yard. express your answer in miles to three significant figures.

Answer 1

Answer:The given range is r = 9010 yards.

Note that

1 mile = 5280 ft

3 ft = 1 yard

Therefore the given range is

r = (9010 \, yd)*(3 \, \frac{ft}{yd} )*( \frac{1}{5280} \, \frac{mi}{ft}) =5.1193 \, mi

Answer: r = 5.119 miles (to 3 sig. figs)

Answer 2

The given range is r = 9010 yards.

Note that
1 mile = 5280 ft
3 ft = 1 yard

Therefore the given range is

`r = (9010 \, yd)*(3 \, (ft)/(yd) )*( (1)/(5280) \, (mi)/(ft)) =5.1193 \, mi`

Answer: r = 5.119 miles (to 3 sig. figs)