Theodore inherited two different stocks whose yearly income was $2100. The total appraised value of the stocks was $40,000 and one was paying 4% and one 6% per year. What was the value of each stock?
so, let the value of stock with 4% = x
And the value of the stock with 6% = y
so,
The yearly income for both = 2100
so, 0.04x + 0.06y = 2100
And, The total appraised value of the stocks was $40,000
so, x + y = 40,000
Solve the system of equations :
0.04 x + 0.06 y = 2100 eq.(1)
x + y = 40,000 eq.(2)
From equation 2: y = 40,000 - x
Substitute with the value of y at the equation (1)
So,
0.04 x + 0.06 ( 40,000 - x ) = 2100
Solve for x
0.04 x + 0.06 * 40,000 - 0.06 x = 2100
combine like terms
0.04 x - 0.06 x = 2100 - 0.06 * 40,000
- 0.02 x = 0