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Cosine law part 2 in need of help (ignore question 67)

Cosine law part 2 in need of help (ignore question 67)-example-1
User Mproffitt
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the law of cosines applies if you have an angle and its sides making it up, so say, if you had angle B and sides "a" and "c", angle B is made by those two sides, and thus the law of cosines would apply to get a missing side or angle.

in this case, we have two angles, B and C and only one side, so.... no dice on the law of cosines then.

now... .let's check closely, B is 66° and C is 28°... wait just a second!, that means A is 180 - ( 66 + 28 ), or 86°.

so then


\bf \cfrac{sin(C)}{c}=\cfrac{sin(A)}{a}\implies \cfrac{sin(28^o)}{11.6}=\cfrac{sin(86^o)}{a}\implies a=\cfrac{11.6\cdot sin(86^o)}{sin(28^o)}

make sure your calculator is in Degree mode.

but "a" is roughly 24.6484428
User Luke Chavers
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