Question

Graph fgh with vertices F (-2,2), G (-2,-4), and H ( -4,-4)

Answer 1

11) We have the vertices F(-2,2), G(-2,-4) and H(-4,-4).

We have to apply a dilation with center at (0,0) and a factor of dilation of k = 3.

A dilation with center at (0,0) has the following rule:

`(x,y)\to(kx,ky)=(3x,3y)`

Then, we can apply this rule to the three vertices as:

`\begin{gathered} F=(-2,2)\to F^(\prime)=(3(-2),3(2))=(-6,6) \\ G=(-2,-4)\to G^(\prime)=(3(-2),3(-4))=(-6,-12) \\ H=(-4,-4)\to H^(\prime)=(3(-4),3(-4))=(-12,-12) \end{gathered}`

We can then graph the pre-image and the image as: