Question

Brahmagupta’s solution to a quadratic equation of the form ax2 + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6? x = x = x = x =

Answer 1

it was A

Explanation:

Answer 2

x = -2.25 or x = 0.92

Explanation:

The given equation is 3x² + 4x -6 = 0

Since the equation is in the form of ax² + bx + c = 0

Therefore solution of the equation will be

`x=\frac{-b\pm \sqrt{b^(2)-4ac}}{2a}=(-4\pm √(16+72))/(6)`

`=(-4\pm √(90))/(6)=(-4\pm 9.49)/(6)`

`x=0.92` Or
`x=-2.25`

Therefore either x = 0.92 is the answer or x = -2.25 is the answer.