Question

Write the equation of the line that passes through the following points: (3,6) (6,7)

Answer 1

The equation of the lien that passes through two coordinates:

`y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)_{}`

Given coordinates : (3,6) (6,7)

`(x_1,y_1)=(3,6)(x_2,y_2)=(6,7)`

Substitute the values and simplify:

`\begin{gathered} y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)_{} \\ y-6=(7-6)/(6-3)(x-3) \\ y-6=(1)/(3)(x-3) \\ 3(y-6)=(x-3) \\ 3y-18=x-3 \\ x-3y-3+18=0 \\ x-3y+15=0 \end{gathered}`

The equation of the line that passes through the following points: (3,6) (6,7)​ is x - 3y + 15 = 0

Answer: x - 3y + 15 = 0