Question

What is the strength of the electric field ep 9.0 mm from a proton?

Answer 1

The strength of the electric field from a proton at a distance of 9.0 mm can be found using Coulomb's law, with the values for Coulomb's constant, the charge of a proton, and the given distance.

Step-by-step explanation:

The strength of the electric field E from a point charge, such as a proton, can be calculated using Coulomb's law, which is E = k|q|/r^2, where k is Coulomb's constant (approximately 8.99 x 10^9 N m^2/C^2), q is the charge of the proton (approximately 1.6 x 10^-19 C), and r is the distance from the charge (9.0 mm = 0.009 m in this case). Plugging in the values, we get E = (8.99 x 10^9 N m^2/C^2)(1.6 x 10^-19 C) / (0.009 m)^2. This will give us the strength of the electric field at 9.0 mm from a proton.

Answer 2

The working equation to be used for this is written below:

E = kQ/d²
where
E is the electric field
k is a constant equal to 8.99 x 10⁹ N m²/C²
Q is the charge
d is the distance

The charge for a proton is equal to 1.6021766208×10⁻¹⁹ C. Substituting the values:

E = (8.99 x 10⁹ N m²/C²)(1.6021766208×10⁻¹⁹ C)/(0.009 m)²
E = 1.778×10⁻⁵ N/C