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What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
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What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?

User Arthur Simas
by
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2 Answers

2 votes

Answer:

2 units

Explanation:

edgenuity 2020

hope this helps!

User Dodger
by
6.6k points
6 votes
x^2 + y^2 + 8x – 6y + 21 = 0
x^2 + 8x +16 + y^2 -6y +9 = -21 + 16 +9
(x+4)^2 + (y-3)^2 = 4
So the radius is 2
User MooMoo
by
7.1k points
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