Question

Suppose it takes 35 min for 1.7 g of sugar to completely react with another reagent we added to the flask. what would the reaction rate be?

Answer 1

The reaction rate is calculated by dividing the change in moles of sucrose (1.7 g converted to moles) by the time taken in hours (35 minutes). For the given mass of sugar, the reaction rate is found to be 8.52 x 10^-3 moles per hour.

Step-by-step explanation:

To calculate the reaction rate of sugar reacting in a flask, we can use the amount of sugar consumed and the time it took for the reaction to complete. In this case, 1.7 g of sugar reacted in 35 minutes. We can express the reaction rate in grams per minute, which is the change in concentration (mass) of the reactant over the change in time.

First, we should convert minutes to hours to match the provided reaction rate unit M/h (where M is moles per liter). 35 minutes is equal to 35/60 hours or approximately 0.583 hours. Next, we need to convert the mass of sugar to moles. Assuming the sugar in question is sucrose (C12H22O11), the molar mass of sucrose is approximately 342.3 g/mol. Therefore, 1.7 g of sucrose is 1.7 g / 342.3 g/mol = 4.97 x 10-3 moles of sucrose.

Now, we can calculate the reaction rate:

Reaction Rate = Change in concentration (moles) / Change in time (hours)

Reaction Rate = 4.97 x 10-3 moles / 0.583 hours = 8.52 x 10-3 moles per hour

If needed, this rate can be converted into M/h by dividing the moles by the volume of solution in liters.

Answer 2

The rate of the reaction can be calculated using the following rule:
rate of reaction = mass / time

For this problem, we have 1.7 grams of sugar reacting in 35 minutes.
Based on this:
rate of reaction = 1.7 / 35 grams/minute

Although we should note that the rate of the chemical would be faster in the beginning of the reaction than in the last minute of the reaction.