As the problem mentions, the mass of fluid added is dependent on the volume of the water. So this means that the independent variable is the volume, and the dependent variable is the ounces of fluid. When you graph the linear equation, the independent variable is along the x-axis and the dependent variable is along the y-axis. So, you actually assign x to ounce of fluid added and y to the volume of water.
Now, we construct the linear equation using the slope-intercept form. Its equation is: y = mx + b, where m is the slope and b is the y-intercept. We can find the slope from at least two given data points. The equation would be
m = (y₂ - y₁) / (x₂ - x₁)
Let's choose two random points: Point 1 (10,000,16) and Point 2 (20,000,32). Note that the points should be written in (x.y) form. So, the slope of the line is equal to:
m = (32 - 16) / (20,000 - 10,000)
m = 1/625
So, the equation is y = x/625 + b. Now, we can determine b by using any point. Suppose we use the third data point, P(30,000, 48). Substitute this to x and y.
48 = 30,000/625 + b
b = 0
Therefore, the linear equation is: y = x/625. The variable y represents the volume of the water in gallons, and the variable x is the mass of fluid added in ounces.