Let us say:
x = Jorge
y = Carla
z = Marcus
a = Dominique
We are given that:
x = 3y --> 1
z = 0.5x --> 2
a = 4y – 2 --> 3
x + y + z + a = 169 --> 4
Substituting 1 to 2:
z = 0.5(3y) = 1.5y --> 5
Substituting 1, 3 and 5 to 4:
3y + y + 4y – 2 + 1.5y = 169
9.5y = 171
y = 18
Hence,
x = 3y = 3*18 = 54
z = 0.5x = 0.5(54) = 27
a = 4y – 2 = 4(18) – 2 = 70
y = 18