Question

If f(x)= -x²+3x+5, find f(-3), f(0), f(2), f(5), and f(8).

Answer 1

f(-3)
-(-3)^2+3(-3)+5
-9-9+5
-18+5
-13 <======

f(0)
-(0)^2+3(0)+5
-0+0+5
5 <=======

f(2)
-(2)^2+3(2)+5
-4+6+5
7 <=======

f(5)
-(5)^2+3(5)+5
-25+15+5
-5 <======

f(8)
-(8)^2+3(8)+5
-64+24+5
-35 <======