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Find a8 in the arithmetic sequence with a1=-7 and d=0.5

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\bf n^(th)\textit{ term of an arithmetic sequence}\\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^(th)\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ ----------\\ a_1=-7\\ d=0.5\\ n=8 \end{cases} \\\\\\ a_8=a_1+(8-1)d\implies a_8=-7+(8-1)(0.5)

and surely you know how much that is.
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