Question

A body starts from rest and moves with uniform acceleration of 6m/s?. What distance does it cover in the third second?

Answer 1

We are given –

• n = 3
• Initial velocity, u = 0 m/s
• Acceleration, a = 6 m/s²

Distance covered in nth seconds –

↠Sn = u + 1/2 × a × (2n-1)

↠Sn = 0 + 1/2 × 6 × (2× 3 -1)

↠Sn = 0 + 3 × (6-1)

↠Sn = 0 + 3 × 5

↠Sn = 15 m

• Henceforth, distance covered in the 3rd sec will be 15 m.