Question

Which of these formulas is correctly rewritten from the original formula to solve for b? a = 3b - 2c?

Answer 1

-3b=-a-2c
b=(a-2c)/-3

Answer 2

`b=(a+2c)/(3)`

Explanation:

We have been given an equation
`a=3b-2c`. We are supposed to solve the given equation for b.

First of all, we will switch sides of the given equation as:

`3b-2c=a`

Let us add
`2c` on both sides:

`3b-2c+2c=a+2c`

`3b=a+2c`

Divide both sides by 3:

`(3b)/(3)=(a+2c)/(3)`

`b=(a+2c)/(3)`

Therefore, our required equation wold be
`b=(a+2c)/(3)`.