Question

Q and r are independent events. if p(q) = 0.8 and p(r) = 0.2, find p(q and r).

Answer 1

P(R)=0.8
P(Q)=0.2
as they are independent
so
P(RandQ)=P(R)×P(Q)
ThenP(RandQ)=P(R)×P(Q) =0.8×0.2 =0.16

Answer 2

The solution is
`P(q \cap r)=0.16`

Explanation:

We need to calculate the
`(p \ \text{and} \ q)`

Given:-
`P(q)=0.8 \ \text{and} \ P(r) =0.2` where q and r are independent events.

Since, Events are independent then
`P(q \cap r)=q * r`

⇒
`P(q \cap r)=q * r`

⇒
`P(q \cap r)=0.8 * 0.2`

⇒
`P(q \cap r)=0.16`

Therefore, the solution is
`P(q \cap r)=0.16`