Question

Factor 6p^2 +15p+9????

Answer 1

actor using the ac method

for
ax²+bx+c when a≠1

multiply a and c and remember their product
find what 2 numbers multiply to get that product and add to be
split b into those 2 numbers
factor

so

first factor the 3
3(2p²+5p+3)
multiply a and c
2*3=6
wat 2 numbers multiply to get 6 and add to 5
oh ya, 2 and 3

3(2p²+2p+3p+3)
gropu and factor
3((2p²+2p)+(3p+3))
3(2p(p+1)+3(p+1))
3(2p+3)(p+1) is factored

Answer 2

To factor the trinomial, you can use the ac method where you multiply the first and last terms together (6 and 9) and add up to 15.
In this case ac= 54
2 numbers that multiply to 54 and add up to 15 would be 6 and 9 so place these numbers where the 15 would be:

`6p^(2) +9p + 6p+9`
Then group terms to simplify:

`(6p^(2) +9p)(6p+9)`
Simplify any like terms:

`3p(2p+3) 3(2p+3)`
And group together again:

`(3p+3)(2p+3)`
You can simplify a 3 out of the first expression one more time to get:

`3(p+1)(2p+3)`
Which would be the factored form. I hope this helps :)