Question

16z+29z=pz−v solve for z

Answer 1

16z + 29z = pz - v....for z
45z = pz - v
45z - pz = -v
z(45 - p) = -v
z = -v / (45 - p) <==

Answer 2

`z = (-v)/(45-p)`

Explanation:

Given the equation:

`16z+29z =pz-v` ....[1]

Solve for z:

Subtract pz from both sides in [1] we have;

`16z+29z-pz = -v`

taking z common we have;

`z(16+29-p)= -v`

Combine like terms;

`z(45-p)= -v`

Divide both sides by (45-p) we have;

`z = (-v)/(45-p)`

Therefore, the value of z is,
`z = (-v)/(45-p)`