Find the equation for the circle with a diameter whose endpoints are (3,1) and (2,1)

Question

asked Nov 27, 2018 159k views

1 Answer

Parse · Answer 1 · 2018-12-02T11:04:05+0000

hello :
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = (3+2)/2 = 5/2 and b = (1+1)/2 =1

let : B(3;1) and ; C (2,1)

r = BC/2

BC = √(3-2)²+(1-1)² ) =1

r = 1/2

the equation for the circle is : (x-5/2)² +(y-1)² = 1/4