Question

Answer? Multiple choice?

Answer 1

Given fraction is

`f(x) = (x^2 + 4x + 3)/(x^2 - 9)`

As we know fraction is not defined where denominator is equal to zero.

So let's find where denominator is zero.


`x^2 - 9 = 0`

We can factorize it as
`a^2 - b^2 = (a+b)(a - b)`

So we can write given equation as


`(x+3)(x-3) = 0`

So x = 3 or x = -3.

So function is undefined at x = 3 and x = -3.

So option 3 is correct.