Question

Find an equation of a line through with m = −3.

Answer 1

`y=-3x+(10)/(9)`

Step-by-step explanation:

Data:

. Slope : m = -3

. Points of the graph:

. . x1 = 1/3

. . y1 = 1/9

Equation form:

`y-y_1=m(x-x_1)`

Solution:

`\begin{gathered} y-(1)/(9)=-3(x-(1)/(3)) \\ y-(1)/(9)=-3x+(3)/(3) \\ y=-3x+(3*3)/(3*3)+(1)/(9) \\ y=-3x+(9)/(9)+(1)/(9) \\ y=-3x+(10)/(9) \end{gathered}`