Question

Solve the following polynomial equation by grouping and factoring. 16y3−25y=0

Answer 1

`\begin{gathered} \text{ Solutions for the polynomial:} \\ y=-(5)/(4),\text{ 0, }(5)/(4) \end{gathered}`

Explanation:

Use common factor to factor ''y'':

`y(16y^2-25)=0`

Now, factor by grouping the perfect binomial:

`\begin{gathered} y(4y+5)(4y-5)=0 \\ \text{ Solve each factor independently:} \\ y=0 \\ \\ 4y+5=0 \\ y=-(5)/(4) \\ \\ 4y-5=0 \\ y=(5)/(4) \end{gathered}`