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Write | √3 - 2i | in a + bi form.

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keeping in mind that, an absolute value expression is in effect a piece-wise, then


\bf |√(3)-2i|\implies \begin{cases} +(√(3)-2i)\\ -(√(3)-2i) \end{cases}\implies \begin{cases} √(3)-2i\\ -√(3)+2i \end{cases}
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