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What is the radius of the circle defined by x^2+2x+y^2+6y-39=0?
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What is the radius of the circle defined by x^2+2x+y^2+6y-39=0?

What is the radius of the circle defined by x^2+2x+y^2+6y-39=0?-example-1
User Yuantonito
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1 Answer

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hello :
x²+2x+y²+6y-39=0
(x²+2x+1)-1 +(y² +6y+9)-9 -39 =0
(x+1)² + (y+3)² = 49 = 7²
the radius is : 7
User Shifatullah
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7.6k points
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